中國網(wǎng)站品牌欄目（頻道）
圣誕節(jié)即將到來，很多父母都開始為給孩子挑選一份完美的圣誕禮物而發(fā)愁。英國心理學(xué)家克利夫?阿諾爾最近創(chuàng)制了一個(gè)完美玩具計(jì)算公式，通過量化玩具價(jià)值，幫助家長找到“完美”玩具。阿諾爾把玩具對(duì)孩子的作用歸納為“玩樂價(jià)值”，計(jì)算公式為：“玩樂價(jià)值”＝T x L + Pi + Po + Cr + S + U + H /
。其中，Pi代表該玩具在孩子獨(dú)自玩耍時(shí)的有用程度；Po為與他人一起玩耍時(shí)的有用程度；Cr是玩具對(duì)創(chuàng)造力的啟發(fā)程度；S代表玩具對(duì)社交能力的開發(fā)；U為實(shí)用性；H為玩具是否可以傳給其他兄弟姐妹們玩；T為預(yù)計(jì)孩子定期玩玩具的時(shí)間（小時(shí)為單位）；L代表孩子被該玩具吸引的總共時(shí)長（以月為單位）；C代表玩具價(jià)格。
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Parents looking for the perfect toy could use mathematics. (Agencies) |
A psychologist has come up with a formula for parents struggling to find the perfect toy for their children this Christmas.
Dr Cliff Arnall, who has previously come up with calculations for the happiest and most depressing day of the year, reckons that mathematics can be used to work out the "play value" of potential purchases.
But parents hoping for a simple formula to help them make wise decisions in the toyshop had better not be in a hurry and might have to bring a calculator with them.
The result is also likely to be different for different children, he admits.
Parents first have to assess the toy against six criteria: its usefulness when playing alone (Pi); playing with others (Po); whether it fosters creativity (Cr); its value promoting social interaction (S); its general utility (U) and finally whether it can be handed down to siblings (H).
Parents must give the toy a score out of five for each and add them up.
In a separate sum, then they must estimate the amount of time in hours a child will play with the toy regularly (T) and multiply it by how many months it is likely to remain of interest (L).
The two figures must then be divided by the square root of the cost (C) and added to the total score from the criteria section.
Simple? For those who did not quite follow, it works out as: T x L + Pi + Po + Cr + S + U + H / square root of C
"A toy may score higher for one child than another but that's an important part of the exercise," said Dr Arnall.
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(Agencies)
（中國日?qǐng)?bào)網(wǎng)英語點(diǎn)津 Helen 編輯）
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